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NIMCET Previous Year Questions (PYQs)

NIMCET Mixture And Alligation PYQ



A vessel contains total 95 litre mixture of milk & water in the ratio of 15 : 4 respectively. P litre of mixture taken out from the vessel and 18 litres water added in the remaining mixture, then the new ratio of milk to water becomes 3 : 2, find the value of P?





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Solution

Mixture Problem: Find the Value of P

Total mixture = 95 L

Initial ratio of milk : water = 15 : 4

Milk = 1519×95=75L
Water = 419×95=20L

Step 1: Let P litres of mixture be removed

Milk removed = 1519×P=15P19
Water removed = 419×P=4P19

Remaining milk = 7515P19
Remaining water = 204P19

After adding 18 L of water:
New water = 204P19+18=384P19

Step 2: According to the new ratio

7515P19384P19=32

Step 3: Cross multiply

2(7515P19)=3(384P19)

15030P19=11412P19

36=18P19

P=36×1918=38

✅ Final Answer: P = 38 litres



A 30 litres mixture of milk and water contains 10% water. How much milk should be added so that the percentage of water in the mixture comes down to 2%?





Go to Discussion


Solution

Milk-Water Mixture Problem

Given: 30 litres mixture contains 10% water ⇒ Water = 3 litres, Milk = 27 litres

Let x litres of milk be added. Total mixture becomes (30 + x) litres. Water remains 3 litres.

We want water to be 2% of the new mixture:

330+x=2100

Solve:

3 / (30 + x) = 2 / 100

⇒ 3 × 100 = 2 × (30 + x)

⇒ 300 = 60 + 2x

⇒ 2x = 240 ⇒ x = 120

✅ Final Answer: 120 litres of milk should be added.



Two liquids A and B are in the ratio 5:1 in container 1 and in the ratio 1:3 in container 2. In what ratio should the contents of the two containers be mixed so as to obtain a mixture of A and B in the ratio 1:1?





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Solution

Let each part be x.
Vol of A= 5x ;
Vol of B= x ; Total Vol= 6x.

Container 2:
Let each part be y.
Vol of A= y ; 
Vol of B= 3y; 
Total Vol= 4y.

After Mixing:
Vol of A= 5x + y
Vol of B= x + 3y
As Ratio of A:B is 1:1, hence
5x+y = x+3y
2x = y
So,
Ratio of Total Vol 1 : Total Vol 2 =
6x / 4y 
= 6x / 4(2x) 
= 6/8 = 3/4.


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